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def solution(n: int, a: list) -> int: # 计算初始总和 original_sum = sum(a) max_sum = origina...

public class Main { public static int solution(int x, int y) { // Edit your code here ...

def solution(n, k, nums): if n == k : return sum(nums) nums = [0]+nums print(nums) pre...

public class Main { public static int[][] dir ={{0,1},{1,0},{-1,0},{0,-1}}; public sta...

def solution(n, a): prefix = [0] * n suffix = [0] * n for i in range(n): prefix[i] = s...

def solution(n: int, a: list, b: list) -> int: MOD = 10**9 + 7 # 初始化动态规划数组 dp = [0, 0,...

from math import gcd from functools import reduce def solution(n: int, a: list) -> str...

def solution(n: int, x: int, y: int, a: list) -> int: # 检查是否已经有逆序对 has_inversion = Fal...

#include #include #include #include using namespace std; std::string solution(int V, i...

#include #include #include int solution(int N) { std::string binary_representation = s...

#include #include #include // 用于格式化输出 using namespace std; string solution(int a, int ...

#include #include using namespace std; int solution(string n) { int max_digit = 0; // ...

#include #include using namespace std; std::string solution(const std::string& t1, con...

def solution(num, data, input): res = set() # 使用集合来去重 for s in data: if s.startswith(i...

#include #include #include int solution(std::vector A) { int N = A.size(); std::vector...

def solution(num): str_num = str(num) # 将数字转成字符串 n = len(str_num) if n == 0: return 0 ...

from bisect import bisect_right from typing import Literal def solution(nodes: list[in...

def min_steps_for_number(num: int) -> int: if num == 0: return 0 if num < 10: return 1...

import math from heapq import heappush, heappop def solution(n: int, s: int, t: int, x...

给定一个数组array_a，数组中的每个元素都可以被规范化到[0,9]的范围内，目标是判断是否存在一个子集，使得该子集内元素之和的个位数等于A或B，或者该子集内元素之和的个...