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def solution(n: int, a: list) -> int: # 计算初始总和 original_sum = sum(a) max_sum = original_sum # 遍历每对相邻

public class Main { public static int solution(int x, int y) { // Edit your code here int temp = 0;

def solution(n, k, nums): if n == k : return sum(nums) nums = [0]+nums print(nums) pre_sum = [0]*(n+

public class Main { public static int[][] dir ={{0,1},{1,0},{-1,0},{0,-1}}; public static int dfs(in

def solution(n, a): prefix = [0] * n suffix = [0] * n for i in range(n): prefix[i] = sum(a[:i+1]) fo

def solution(n: int, a: list, b: list) -> int: MOD = 10**9 + 7 # 初始化动态规划数组 dp = [0, 0, 0] dp[0] = 1

from math import gcd from functools import reduce def solution(n: int, a: list) -> str: def prime_fa

def solution(n: int, x: int, y: int, a: list) -> int: # 检查是否已经有逆序对 has_inversion = False for i in ra

#include #include #include #include using namespace std; std::string solution(int V, int W) { if(V==