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Solution Tricky part is to figure out how to encode the string.

solution: First take a look at a few cases: 1,2,3,4 -> 0 1,1,1,1,1,2 -> 4 1,1,1,1,2 -> 3 Which makes

Solution: DFS + Trie The key is how we find the matches of word from the dictionary. We can use hash

Solution: BFS while (!queue.isEmpty()) { int curCourse = queue.poll();

Solution BFSt minimumSemesters(int n, int[][] relations) { int[] inDegree = new int[n + 1];

 ```java class Solution { public d

 ```java class MyHashSet { private

Solution: Array + LinkedList706. Design HashMap706. Design HashMap706. Design HashMap706. Design Has

 ```java class Solution { public b