c语言-作业

(1)奇数累加 s = 1 + 3 + 5 + 7 +...+ 9

#include <stdio.h>

 int main(){
 	int s = 0 ;
 	int i = 1 ;
        
 	while(i <= 100){
 		printf("%d \n",i);
 		s = s + i;
		i+=2; 
	}
 
 	printf("1 + 3 + 5 + 7 + ... + 99的和为：%d \n",s);
	return 0;
 }

(2)偶数累加 s = 2 + 4 + 6 + 8 +...+ 100

#include <stdio.h>

 int main(){
 	int s = 0 ;
 	int i = 2 ;
 	
 	while(i <= 100){
 		printf("%d \n",i);
 		s += i;
		i +=2; 
	}
	
 	printf("2 + 4 + 6 + 8 + ... + 100的和为：%d \n" , s);
	return 0;
 }

运行效果图