题目：// s=1-1/2+1/3-1/4+1/5-1/6...+1/19
如下就是c语言程序
#include<stdio.h>
int main(){
double s =0;
int i = 1;
while(i<= 19 ){
printf("%d \n",i);
if(i%2 == 0){
s -= 1.0/i;
}else{
s += 1.0/i;
}
i++;
}
printf("s=%f \n",s);
return 0;
}
运行结果
