题目:输入月份,输出当月天数
要求:1-->31 2-->继续询问用户,请输入年份,根据是否闰年判断,输出28,29 3-->31 4-->30
#include<stdio.h>
#include <stdlib.h>
int main(){
//输入月份,输出当月天数
// 1-->31
//2-->继续询问用户,请输入年份,根据是否闰年判断,输出28,29
//3-->31
//4-->30
int month, year, days;
printf("请输入月份(1-12):");
scanf("%d", &month);
switch (month) {
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
days = 31;
break;
case 4:
case 6:
case 9:
case 11:
days = 30;
break;
case 2:
printf("请输入年份:");
scanf("%d", &year);
if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
days = 29;
} else {
days = 28;
}
break;
default:
printf("输入的月份无效!\n");
return 1;
}
printf("%d月有%d天\n", month, days);
return 0;
}
演示如下: