二叉树前中后序遍历(迭代做法)
二叉树的前中后序遍历用递归来做的话很简单,用迭代来做,其实就是把递归的过程用栈模拟出来。
二叉树的前序遍历
class Solution {
public:
vector<int> preorderTraversal(TreeNode* root) {
vector<int>ans;
if(root==nullptr)return ans;
stack<TreeNode*>stk;
TreeNode* node=root;
while(!stk.empty()||node){
while(node){
ans.push_back(node->val);
stk.push(node);
node=node->left;
}
node=stk.top();
stk.pop();
node=node->right;
}
return ans;
}
};
二叉树的中序遍历
class Solution {
public:
vector<int> inorderTraversal(TreeNode* root) {
vector<int> ans;
stack<TreeNode*> stk;
while (root != nullptr || !stk.empty()) {
while (root != nullptr) {
stk.push(root);
root = root->left;
}
root=stk.top();
stk.pop();
ans.push_back(root->val);
root=root->right;
}
return ans;
}
};
二叉树的后序遍历
class Solution {
public:
vector<int> postorderTraversal(TreeNode *root) {
vector<int> res;
if (root == nullptr) {
return res;
}
stack<TreeNode *> stk;
TreeNode *prev = nullptr;
while (root != nullptr || !stk.empty()) {
while (root != nullptr) {
stk.emplace(root);
root = root->left;
}
root = stk.top();
stk.pop();
if (root->right == nullptr || root->right == prev) {
res.emplace_back(root->val);
prev = root;
root = nullptr;
} else {
stk.emplace(root);
root = root->right;
}
}
return res;
}
};