在 PyScripter 中处理和终止无限循环时，以下是一些实用技巧和建议，可以帮助你高效地中断运行，避免环境卡死或不必要的操作。
问题背景
在使用 Python (具体版本为 PyScripter) 进行编程时，我遇到了一段无法自动终止的代码，导致程序一直处于循环状态。以下就是这段代码：
def main():
pass
if __name__ == '__main__':
main()
import random
def GuessingGame():
yes = ['y', 'Y', 'Yes', 'yes']
rng = random.Random()
number_to_guess = rng.randrange(1, 11)
correct_guesses = 0
win_percent = 0
attempts = 0
name = input('What is your name? ')
print('Nice to meet you', name, '! I am going to pick a random number and you will have 3 tries to guess it.'
'Good luck!')
while attempts < 3:
guess = int(input('Guess the number I have chosen between 1 and 10. '))
attempts += 1
if guess == number_to_guess:
print('Great guess, you are right', name, '!')
correct_guesses += 1
win_percent = float((correct_guesses * 100) / attempts)
print('You have', correct_guesses, 'correct guesses!')
print('You are right', win_percent, 'of the time.')
elif guess > number_to_guess:
print('The number is lower than', guess, "!")
elif guess < number_to_guess:
print('The number is higher than', guess, "!")
else:
print('Wrong, the number was', number_to_guess, '!')
print('You have', correct_guesses, 'correct guesses!')
print('You are right', win_percent, 'of the time.')
game_over = input("Do you want to play again? Yes or No? ")
while game_over in yes:
GuessingGame()
else:
exit()
print('The program will now terminate. Goodbye.')
GuessingGame()
这段代码实现了一个简单的数字猜谜游戏，用户需要在三次机会内猜出随机生成的数字。问题在于，当用户选择重新开始游戏时，代码会再次调用 GuessingGame() 函数，导致代码陷入无限循环。
解决方案
为了解决这个问题，我们需要对代码进行修改，使其在用户选择重新开始游戏时能够正确终止。我们可以通过添加一个条件来实现这一点，即当用户选择重新开始游戏时，才调用 GuessingGame() 函数。
以下是如何修改代码以解决此问题的步骤：
- 在 while game_over in yes: 循环中添加一个条件来检查用户是否输入了 "Yes"。
- 如果用户输入了 "Yes"，则调用 GuessingGame() 函数。
- 如果用户输入了 "No"，则终止程序。
以下是修改后的代码：
def main():
pass
if __name__ == '__main__':
main()
import random
def GuessingGame():
yes = ['y', 'Y', 'Yes', 'yes']
rng = random.Random()
number_to_guess = rng.randrange(1, 11)
correct_guesses = 0
win_percent = 0
attempts = 0
name = input('What is your name? ')
print('Nice to meet you', name, '! I am going to pick a random number and you will have 3 tries to guess it.'
'Good luck!')
while attempts < 3:
guess = int(input('Guess the number I have chosen between 1 and 10. '))
attempts += 1
if guess == number_to_guess:
print('Great guess, you are right', name, '!')
correct_guesses += 1
win_percent = float((correct_guesses * 100) / attempts)
print('You have', correct_guesses, 'correct guesses!')
print('You are right', win_percent, 'of the time.')
elif guess > number_to_guess:
print('The number is lower than', guess, "!")
elif guess < number_to_guess:
print('The number is higher than', guess, "!")
else:
print('Wrong, the number was', number_to_guess, '!')
print('You have', correct_guesses, 'correct guesses!')
print('You are right', win_percent, 'of the time.')
game_over = input("Do you want to play again? Yes or No? ")
while game_over in yes:
if game_over in yes:
GuessingGame()
else:
exit()
print('The program will now terminate. Goodbye.')
通过添加条件来检查用户是否输入了 "Yes"，我们可以确保代码在用户选择重新开始游戏时才调用 GuessingGame() 函数，从而避免了无限循环的问题。
通过这些技巧，我们可以更高效地在 PyScripter 中终止无限循环，同时优化代码设计，避免重复发生类似问题。
