1. toSorted()
before:
const numbers = [3, 1, 4, 1, 5];
const sorted = [...numbers].sort((a, b) => a - b);
console.log(sorted); // [1, 1, 3, 4, 5]
console.log(numbers); // [3, 1, 4, 1, 5]
now:
const numbers = [3, 1, 4, 1, 5];
const sorted = numbers.toSorted((a, b) => a - b);
console.log(sorted); // [1, 1, 3, 4, 5]
console.log(numbers); // [3, 1, 4, 1, 5]
2. toReversed()
before:
const numbers = [1, 2, 3, 4, 5];
const reversed = numbers.reverse();
console.log(reversed); // [5, 4, 3, 2, 1]
console.log(numbers); // [5, 4, 3, 2, 1]
now:
const numbers = [1, 2, 3, 4, 5];
const reversed = numbers.toReversed();
console.log(reversed); // [5, 4, 3, 2, 1]
console.log(numbers); // [1, 2, 3, 4, 5]
3. toSpliced()
const items = [1, 2, 3, 4, 5];
const newItems = items.toSpliced(2, 1, 6, 7);
console.log(newItems); // [1, 2, 6, 7, 4, 5]
console.log(items); // [1, 2, 3, 4, 5]
4. 从末尾开始查找数组
const numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
const lastEven = numbers.findLast(n => n % 2 === 0);
console.log(lastEven); // 10（正确）
5. 数组的with()方法
before:
const arr = [1, 2, 3, 4, 5];
const newArr = [...arr];
newArr[2] = 6;
console.log(newArr); // [1, 2, 6, 4, 5]
console.log(arr); // [1, 2, 3, 4, 5]
now:
const arr = [1, 2, 3, 4, 5];
const newArr = arr.with(2, 6);
console.log(newArr); // [1, 2, 6, 4, 5]
console.log(arr); // [1, 2, 3, 4, 5]
