【Leetcode 1684 】 统计一致字符串的数目—— 哈希表

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给你一个由不同字符组成的字符串 allowed 和一个字符串数组 words 。如果一个字符串的每一个字符都在 allowed 中,就称这个字符串是 一致字符串

请你返回 words 数组中 一致字符串 的数目。

示例 1:

输入: allowed = "ab", words = ["ad","bd","aaab","baa","badab"]
输出: 2
解释: 字符串 "aaab""baa" 都是一致字符串,因为它们只包含字符 'a''b'

示例 2:

输入: allowed = "abc", words = ["a","b","c","ab","ac","bc","abc"]
输出: 7
解释: 所有字符串都是一致的。

示例 3:

输入: allowed = "cad", words = ["cc","acd","b","ba","bac","bad","ac","d"]
输出: 4
解释: 字符串 "cc""acd""ac""d" 是一致字符串。

哈希表

function countConsistentStrings(allowed: string, words: string[]): number {
  const allowedSet = new Set<string>(allowed);
  const filterWords = words.filter((word) => {
    for (const char of word) {
      if (!allowedSet.has(char)) return false;
    }
    return true;
  });
  return filterWords.length;
}