203. 移除链表元素 - 力扣(LeetCode)
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode removeElements(ListNode head, int val) {
ListNode dummy = new ListNode(0);
dummy.next = head;
head = dummy;
while (head.next != null) {
if (head.next.val == val) {
head.next = head.next.next;
} else {
head = head.next;
}
}
return dummy.next;
}
}
707. 设计链表 - 力扣(LeetCode)
class MyLinkedList {
int size;
ListNode head;
public MyLinkedList() {
size = 0;
head = new ListNode(0);
}
public int get(int index) {
if(index<0 || index >= size){
return -1;
}
ListNode cur = head;
for(int i = 0;i <= index;i++){
cur = cur.next;
}
return cur.val;
}
public void addAtHead(int val) {
addAtIndex(0,val);
}
public void addAtTail(int val) {
addAtIndex(size,val);
}
public void addAtIndex(int index, int val) {
if(index > size){
return;
}
index = Math.max(0,index);
size++;
ListNode pred = head;
for(int i = 0;i<index;i++){
pred = pred.next;
}
ListNode toAdd = new ListNode(val);
toAdd.next = pred.next;
pred.next = toAdd;
}
public void deleteAtIndex(int index) {
if(index <0 || index >= size){
return;
}
size--;
ListNode pred = head;
for(int i = 0;i<index;i++){
pred = pred.next;
}
pred.next = pred.next.next;
}
}
class ListNode{
int val;
ListNode next;
public ListNode(int val){
this.val = val;
}
}
这道题,有一个要点在于addAtIndex()中循环i<=index.
206. 反转链表 - 力扣(LeetCode)
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode reverseList(ListNode head) {
ListNode prev = null;
ListNode curr = head;
while(curr != null){
ListNode next = curr.next;
curr.next = prev;
prev = curr ;
curr = next ;
}
return prev;
}
}
好题,不知道自己学会没,以后可以复习一下,可能会有新的感悟。