- 用最少数量的箭引爆气球 leetcode.com/problems/mi…
class Solution {
public int findMinArrowShots(int[][] points) {
// 根据气球直径的开始坐标从小到大排序
// 使用Integer内置比较方法,不会溢出
Arrays.sort(points, (a, b) -> Integer.compare(a[0], b[0]));
int count = 1; // points 不为空至少需要一支箭
for (int i = 1; i < points.length; i++) {
if (points[i][0] > points[i - 1][1]) { // 气球i和气球i-1不挨着,注意这里不是>=
count++; // 需要一支箭
} else { // 气球i和气球i-1挨着
points[i][1] = Math.min(points[i][1], points[i - 1][1]); // 更新重叠气球最小右边界
}
}
return count;
}
}
class Solution {
public int eraseOverlapIntervals(int[][] intervals) {
Arrays.sort(intervals, (a,b)-> {
return Integer.compare(a[0],b[0]);
});
int remove = 0;
int pre = intervals[0][1];
for(int i = 1; i < intervals.length; i++) {
if(pre > intervals[i][0]) {
remove++;
pre = Math.min(pre, intervals[i][1]);
}
else pre = intervals[i][1];
}
return remove;
}
}
763.划分字母区间 leetcode.com/problems/pa…
class Solution {
public List<Integer> partitionLabels(String S) {
List<Integer> list = new LinkedList<>();
int[] edge = new int[26];
char[] chars = S.toCharArray();
for (int i = 0; i < chars.length; i++) {
edge[chars[i] - 'a'] = i;
}
int idx = 0;
int last = -1;
for (int i = 0; i < chars.length; i++) {
idx = Math.max(idx,edge[chars[i] - 'a']);
if (i == idx) {
list.add(i - last);
last = i;
}
}
return list;
}
}