【书生大模型实战营】python笔记python对字符串有很多方法。针对这题，可以想到先把标点符号换成空格，再利用spl

请实现一个wordcount函数，统计英文字符串中每个单词出现的次数。返回一个字典，key为单词，value为对应单词出现的次数。

Input:

"""Hello world!  
This is an example.  
Word count is fun.  
Is it fun to count words?  
Yes, it is fun!"""

Output:

{'hello': 1, 'world': 1, 'this': 1, 'is': 4, 'an': 1, 'example': 1, 'word': 1, 'count': 2,
'fun': 3, 'it': 2, 'to': 1, 'words': 1, 'yes': 1}

TIPS：记得先去掉标点符号,然后把每个单词转换成小写。不需要考虑特别多的标点符号，只需要考虑实例输入中存在的就可以。

text = """
Got this panda plush toy for my daughter's birthday,
who loves it and takes it everywhere. It's soft and
super cute, and its face has a friendly look. It's
a bit small for what I paid though. I think there
might be other options that are bigger for the
same price. It arrived a day earlier than expected,
so I got to play with it myself before I gave it
to her.
"""

def wordcount(text):
    pass

python对字符串有很多方法。针对这题，可以想到先把标点符号换成空格，再利用split（）分割空格，这样得到所有单词的列表。根据列表在字符串里一个个找出现次数。

有个小问题，给的字符串里存在缩写：It‘s，也存在不是缩写daughter’s。因为题目说只针对该字符串，所以单独考虑一下就好。

替换用replace（）函数。有换行符也要注意替换成空格。