Python输出62进制3位数秩序代码正确版

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import re z = ["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"] for i in range(0,62): for j in range(0,62): for k in range(0,62): print("%s%s%s" % ( z[i],z[j],z[k]))