c语言输出8进制随机数量四则运算口诀表代码正确例题 - 副本 (6)

#include <stdio.h> #include <stdlib.h> #include <time.h> // 函数用于将整数转换为指定基数的字符串表示 char* intToBaseString(int num, int base) { static char buffer[33]; // 静态数组用于存储转换后的字符串 int i = 0; int isNegative = 0;

// 处理负数
if (num < 0) {
    isNegative = 1;
    num = -num;
}

// 转换为字符串
do {
    int digit = num % base;
    buffer[i++] = digit < 10 ? '0' + digit : 'A' + digit - 10;
    num /= base;
} while (num > 0);

// 如果是负数，添加负号
if (isNegative) {
    buffer[i++] = '-';
}

// 字符串结束符
buffer[i] = '\0';

// 反转字符串
for (int j = 0; j < i / 2; j++) {
    char temp = buffer[j];
    buffer[j] = buffer[i - j - 1];
    buffer[i - j - 1] = temp;
}

return buffer;

}

int main() {

int n, m, o,d;
char r[33], s[33], t[33]; // 为字符串分配足够的空间

srand((int)time(NULL)); for (n = 0; n <(rand() % 100); n++) { for (m = 0; m < (rand() % 100); m++) { o = n + m; // 调用函数将整数转换为基数为8的字符串 strcpy(r, intToBaseString(n, 8)); strcpy(s, intToBaseString(m, 8)); strcpy(t, intToBaseString(o, 8));

        // 输出结果
        printf("%s+%s=%s\n", r, s, t);

    }
}

return 0;

}

改编以上程序代码增加功能实现四则运算口诀表代码

以下是修改后的代码，实现了四则运算口诀表的功能：

c 复制#include <stdio.h> #include <stdlib.h> #include <time.h>

// 函数用于将整数转换为指定基数的字符串表示 char* intToBaseString(int num, int base) { static char buffer[33]; // 静态数组用于存储转换后的字符串 int i = 0; int isNegative = 0;

// 处理负数
if (num < 0) {
    isNegative = 1;
    num = -num;
}

// 转换为字符串
do {
    int digit = num % base;
    buffer[i++] = digit < 10? '0' + digit : 'A' + digit - 10;
    num /= base;
} while (num > 0);

// 如果是负数，添加负号
if (isNegative) {
    buffer[i++] = '-';
}

// 字符串结束符
buffer[i] = '\0';

// 反转字符串
for (int j = 0; j < i / 2; j++) {
    char temp = buffer[j];
    buffer[j] = buffer[i - j - 1];
    buffer[i - j - 1] = temp;
}

return buffer;

}

int main() {

int n, m, o, p, q, r;
char r1[33], s1[33], t1[33], t2[33], t3[33], t4[33]; // 为字符串分配足够的空间

srand((int)time(NULL));

for (n = 0; n < (rand() % 100); n++) {
    for (m = 0; m < (rand() % 100); m++) {
        o = n + m;
        p = n - m;
        q = n * m;
        if (m!= 0) {
            r = n / m;
        }

        // 调用函数将整数转换为基数为 8 的字符串
        strcpy(r1, intToBaseString(n, 8));
        strcpy(s1, intToBaseString(m, 8));
        strcpy(t1, intToBaseString(o, 8));
        strcpy(t2, intToBaseString(p, 8));
        strcpy(t3, intToBaseString(q, 8));
        if (m!= 0) {
            strcpy(t4, intToBaseString(r, 8));
        }

        // 输出结果
        printf("%s + %s = %s\n", r1, s1, t1);
        printf("%s - %s = %s\n", r1, s1, t2);
        printf("%s * %s = %s\n", r1, s1, t3);
        if (m!= 0) {
            printf("%s / %s = %s\n", r1, s1, t4);
        }
    }
}

return 0;

}