1. 题目描述
给定一个24小时制(小时:分钟 "HH:MM")的时间列表,找出列表中任意两个时间的最小时间差并以分钟数表示。
2. 题目示例
2.1 示例1
输入:timePoints = ["23:59","00:00"]
输出:1
2.2 示例2
输入:timePoints = ["00:00","23:59","00:00"]
输出:0
2.3 提示
timePoints[i]格式为"HH:MM"
3. 解题思路
保存当天时间和第第二天时间
4. 解题代码
4.1 python
class Solution:
def findMinDifference( self,timePoints: List[str]) -> int:
nums, idx = [], 0
for time in timePoints:
h, m = int(time[:2]), int(time[-2:])
nums.append(h * 60 + m)
nums.append(h * 60 + m + 1440)
nums.sort()
return min(nums[i ] - nums[i-1] for i in range(1,len(nums)))