无涯教程-PHP - ctype_punct()函数

ctype_punct() - 语法

ctype_punct ( $text );

此函数检查提供的字符串text中的所有字符是否都是标点符号。

ctype_punct() - 返回值

如果文本中的每个字符都是可打印的，则返回TRUE，但既不是字母、数字也不是空白，否则返回FALSE。

ctype_punct() - 示例

<?php
   $strings=array(k211!@!0, foo!#, *);
   
   foreach ($strings as $test) {
      if (ctype_punct($test)) {
         echo "$test consists of all punctuation.\n";
      }else {
         echo "$test does not have all punctuation.\n";
      }
   }
?> 

这将产生以下输出-

k211!@!$# does not have all punctuation.
foo!#$bar does not have all punctuation.
*$()  consists of all punctuation.

参考链接

www.learnfk.com/php/php-fun…