给你一个链表,删除链表的倒数第 n **个结点,并且返回链表的头结点。
示例 1:
输入: head = [1,2,3,4,5], n = 2
输出: [1,2,3,5]
示例 2:
输入: head = [1], n = 1
输出: []
示例 3:
输入: head = [1,2], n = 1
输出: [1]
提示:
- 链表中结点的数目为
sz 1 <= sz <= 300 <= Node.val <= 1001 <= n <= sz
题解:
class Solution {
public ListNode removeNthFromEnd(ListNode head, int n) {
ListNode dummy=new ListNode(0,head);
ListNode first=head;
ListNode second=dummy;
for(int i=0;i<n;i++){
first=first.next;
}
while(first!=null){
first=first.next;
second=second.next;
}
second.next=second.next.next;
return dummy.next;
}
}