问题
Implement the built-in Pick<T, K> generic without using it.
Constructs a type by picking the set of properties K from T
For example:
interface Todo {
title: string
description: string
completed: boolean
}
type TodoPreview = MyPick<Todo, 'title' | 'completed'>
const todo: TodoPreview = {
title: 'Clean room',
completed: false,
}
解答
type MyPick<T extends Record<string, any>, U> = { [P in Extract<keyof Todo, U>]: T[P] }