


方法
- 两个玩家,其中一个玩家下棋,在格子里记1分,另一个记-1。
- 产生赢家的条件:某一行/某一列/两个对角线之一 的分数为3或者-3

class Solution {
public String tictactoe(int[][] moves) {
int n = 3;
int[] rowScore = new int[n], colScore = new int[n];
int diagonol1Score = 0, diagonol2Score = 0;
int player = 1;
for (int[] move : moves) {
int row = move[0], col = move[1];
rowScore[row] += player;
colScore[col] += player;
if (row == col) {
diagonol1Score += player;
}
if (row + col + 1 == n) {
diagonol2Score += player;
}
if (Math.abs(rowScore[row]) == n || Math.abs(colScore[col]) == n
|| Math.abs(diagonol1Score) == n || Math.abs(diagonol2Score) == n) {
return player == 1 ? "A" : "B";
}
player *= -1;
}
return moves.length == n * n ? "Draw" : "Pending";
}
}