算法修炼Day44|474. 一和零 ● 518. 零钱兑换 II ● 377. 组合总和 Ⅳ

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题目:474. 一和零 - 力扣(LeetCode)
代码实现:
class Solution {
    public int findMaxForm(String[] strs, int m, int n) {
        int[][] dp = new int[m + 1][n + 1];
        for (String str : strs) {
            int one = 0, zero = 0;
            char[] ch = str.toCharArray();
            for (int i = 0; i < ch.length; i++) {
                if (ch[i] == '0') {
                    zero++;
                } else {
                    one++;
                }
            }
            for (int i = m; i >= zero; i--) {
                for (int j = n; j >= one; j--) {
                    dp[i][j] = Math.max(dp[i][j], dp[i - zero][j - one] + 1);
                }
            }
        }
        return dp[m][n];
    }
}
题目:518. 零钱兑换 II - 力扣(LeetCode)
代码实现:
class Solution {
    public int change(int amount, int[] coins) {
        int[] dp = new int[amount + 1];
        dp[0] = 1;
        for (int i = 0; i < coins.length; i++) {
            for (int j = coins[i]; j <= amount; j++) {
                dp[j] += dp[j - coins[i]];
            }
        }
        return dp[amount];
    }
}
题目:377. 组合总和 Ⅳ - 力扣(LeetCode)
代码实现:
class Solution {
    public int combinationSum4(int[] nums, int target) {
        int[] dp = new int[target + 1];
        dp[0] = 1;
        for (int i = 0; i <= target; i++) {
            for (int j = 0; j < nums.length; j++) {
                if (i >= nums[j]) {
                    dp[i] += dp[i - nums[j]];
                }
            }
        }
        return dp[target];
    }
}