算法修炼Day18|513.找树左下角的值 ● 112. 路径总和 113.路径总和ii ● 106.从中序与后序遍历序列构造二叉树 105.从前序与中序遍历

题目：513. 找树左下角的值 - 力扣（LeetCode）

代码实现：

// 莫名其妙打开丢失
class Solution {
    private int Deep = -1;
    private int value = 0;
    public int findBottomLeftValue(TreeNode root) {
        value = root.val;
        findLeftValue(root,0);
        return value;
    }

    private void findLeftValue (TreeNode root,int deep) {
        if (root == null) return;
        if (root.left == null && root.right == null) {
            if (deep > Deep) {
                value = root.val;
                Deep = deep;
            }
        }
        if (root.left != null) findLeftValue(root.left,deep + 1);
        if (root.right != null) findLeftValue(root.right,deep + 1);
    }
}

题目：112. 路径总和 - 力扣（LeetCode）

代码实现：

class Solution {
    public boolean hasPathSum(TreeNode root, int targetSum) {
        if (root == null) return false;
        targetSum -= root.val;
        if (root.left == null && root.right == null) {
            return targetSum == 0;
        }
        if (root.left != null) {
            boolean left = hasPathSum(root.left, targetSum);
            if (left) {
                return true;
            }
        }
        if (root.right != null) {
            boolean right = hasPathSum(root.right, targetSum);
            if (right) return true;
        }
        return false;
    }
}