判断新旧VNode是不是相同的
function isSameVNodeType(n1, n2) {
if (n2.shapeFlag & 6 && hmrDirtyComponents.has(n2.type)) {
n1.shapeFlag &= ~256;
n2.shapeFlag &= ~512;
return false;
}
return n1.type === n2.type && n1.key === n2.key;
}
patch中间对比使用key建立一个 keyToNewIndexMap
- 不使用key两层遍历对比,复杂度是On2,
- 使用key,复杂度是On,使用key直接原因
function patchKeyedChildren() {
const keyToNewIndexMap = new Map();
for (i = s2; i <= e2; i++) {
const nextChild = (c2[i] = optimized
? cloneIfMounted(c2[i])
: normalizeVNode(c2[i]));
if (nextChild.key != null) {
if (keyToNewIndexMap.has(nextChild.key)) {
warn(
`Duplicate keys found during update:`,
JSON.stringify(nextChild.key),
`Make sure keys are unique.`
);
}
keyToNewIndexMap.set(nextChild.key, i);
}
}
let j;
let patched = 0;
const toBePatched = e2 - s2 + 1;
let moved = false;
let maxNewIndexSoFar = 0;
const newIndexToOldIndexMap = new Array(toBePatched);
for (i = 0; i < toBePatched; i++) newIndexToOldIndexMap[i] = 0;
for (i = s1; i <= e1; i++) {
const prevChild = c1[i];
if (patched >= toBePatched) {
unmount(prevChild, parentComponent, parentSuspense, true);
continue;
}
let newIndex;
if (prevChild.key != null) {
newIndex = keyToNewIndexMap.get(prevChild.key);
} else {
for (j = s2; j <= e2; j++) {
if (
newIndexToOldIndexMap[j - s2] === 0 &&
isSameVNodeType(prevChild, c2[j])
) {
newIndex = j;
break;
}
}
}
}