一、数组指定格式打印
@Test
public void format(){
int[] arr = {1, 2, 3, 4, 5, 6};
execute(arr);
}
public void execute(int [] arr){
System.out.print("[");
for (int i = 0; i < arr.length; i++) {
if(i==arr.length-1){
System.out.print(arr[i]);
}else {
System.out.print(arr[i]+",");
}
}
System.out.print("]");
}
二、求数组中的最大值
@Test
public void max(){
//求数组中的最大值
int[] arr = {1, 2, 3, 4, 5, 6}
int max = getMax(arr)
System.out.println(max)
}
public int getMax(int [] arr){
int max = arr[0]
for (int i = 0
if(arr[i]>max){
max=arr[i]
}
}
return max
}
三、判断数组中是否存在对应的元素
@Test
public void whetherExist(){
int[] arr = {1, 2, 3, 4, 5, 6};
boolean getresult = getresult(arr, 99);
System.out.println(getresult);
}
public boolean getresult(int []arr,int number){
for (int i = 0; i < arr.length; i++) {
if(arr[i]==number){
return true;
}
}
return false;
}
四、根据淡旺季求出飞机票价格
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("请输入机票的原价:");
int money = scanner.nextInt();
System.out.println("请输入月份:");
int month = scanner.nextInt();
System.out.println("请输入头等舱还是经济舱:0 代表头等舱 1 代表经济舱");
int grade = scanner.nextInt();
if(month>=5&&month<=10){
money = getMoney(money, grade, 0.9, 0.85);
}else if((month>=11&&month<=12)||(month>=1&&month<=4)){
money = getMoney(money, grade, 0.7, 0.65);
}else{
System.out.println("输入的月份不合法!");
}
System.out.println("您的机票价格为:"+money);
}
private static int getMoney(int money, int grade, double v, double v2) {
if (grade == 0) {
money = (int) (money * v);
} else if (grade == 1) {
money = (int) (money * v2);
} else {
System.out.println("输入的等级不对");
}
return money;
}
五、范围内找质数
@Test
//在101~200范围内的质数
public void rangePrimeNumber() {
int count = 0
for (int i = 101
boolean result = true
for (int j = 2
//判断是否被整除
if (i % j == 0) {
result = false
break
}
}
if (result) {
System.out.println(i + "是一个质数")
count++
}
}
System.out.println("质数有:" + count + "个")
}
}
六、随机生成验证码
public class Captcha {
public static void main(String[] args) {
//定义一个方法随机产生一个5位数的验证码
//格式为: 长度为5 前四位是大写字母或者小写字母最后一位是数字
char[] chars = new char[52]
for (int i = 0
//ASCII码表
if (i <= 25) {
//添加小写字母
chars[i] = (char) (97 + i)
} else {
//添加大写字母
chars[i] = (char) (65 + i - 26)
}
}
//定义一个字符串来记录最后的结果
String result = ""
//随机抽取4次数组中的索引
Random random = new Random()
for (int i = 0
int randomIndex = random.nextInt(chars.length)
result = result + chars[randomIndex]
}
//随机生成一个0~9的数字
int number = random.nextInt(10)
result += number
System.out.println("验证码:" + result)
}
}
七、评委打分
public class JudgesScores {
public static void main(String[] args) {
//通过6为评委打分去除最高分和最低分求平均分即为选手最终分数
int[] ints = addScore()
int sum = 0
for (int i = 0
sum += ints[i]
}
int max = getmax(ints)
int min = getmin(ints)
int avg = (sum - max - min) / (ints.length - 2)
System.out.println("选手的最终得分为:" + avg)
}
//把分数添加进入数组中
public static int[] addScore() {
int[] scoreArr = new int[6]
Scanner scanner = new Scanner(System.in)
for (int i = 0
System.out.println("请评委" + (i + 1) + "给出分数:")
int score = scanner.nextInt()
if (score >= 0 || score < 101) {
scoreArr[i] = score
i++
} else {
System.out.println("输入分数有误请重新输入")
}
}
return scoreArr
}
//求数组中的最大值
public static int getmax(int[] scoreArr) {
int max = scoreArr[0]
for (int i = 0
if (scoreArr[i] > max) {
max = scoreArr[i]
}
}
return max
}
//求数组中的最小值
public static int getmin(int[] scoreArr) {
int min = scoreArr[0]
for (int i = 0
if (scoreArr[i] < min) {
min = scoreArr[i]
}
}
return min
}
}
八、密码的加密与解密
public class PassWord {
public static void main(String[] args) {
//对系统密码进行加密操作
//格式:每位数字加上5,在对10求余,最后将所有的数字反转
int number = 1983
//将密码赋值给一个临时数据
int temp = number
int count = 0
//判断密码的长度
while (number != 0) {
number = number / 10
count++
}
//将密码进行拆分倒着存入数组当中
int[] arr = new int[count]
int index = arr.length - 1
while (temp != 0) {
int ge = temp % 10
temp = temp / 10
arr[index] = ge
index--
}
//加密操作
//对数组中每个数字加5
for (int i = 0
arr[i] = arr[i] + 5
}
//对数组中每个数字对10求余
for (int i = 0
arr[i] = arr[i] % 10
}
//对数组中的数据进行反转
for (int i = 0, j = arr.length - 1
int temp1 = arr[i]
arr[i] = arr[j]
arr[j] = temp1
}
//解密操作
//对数组进行反转
for (int i = 0, j = arr.length - 1
int temp1 = arr[i]
arr[i] = arr[j]
arr[j] = temp1
}
//由于加密是通过对10取余进行获取的所以解密需进行判断
//在0~4之间加10在5~9之间数字不变
for (int i = 0
if (arr[i] > 0 && arr[i] < 5) {
arr[i] = arr[i] + 10
}
}
//在减5
for (int i1 = 0
arr[i1] = arr[i1] - 5
}
//对数组中的元素进行拼接
int result = 0
for (int i1 = 0
result = result * 10 + arr[i1]
}
System.out.println("原密码为:" + result)
}
}