逢7过游戏

while 循环

# 需求: 100之内逢7过游戏,7的倍数或者包含7的说'过'
# 分析: 7的倍数: i%7==0   个位是7: i%10==7  十位是7: i//10==7
# 初始变量
i = 1
# 条件判断
while i < 100:
    # 循环体
    if i % 7 == 0 or i % 10 == 7 or i // 10 == 7:
        print("过")
    else:
        print(i)
    # 条件控制
    i += 1

for 循环

for i in range(1,100):
    if i % 7 == 0 or i % 10 == 7 or i // 10 == 7:
        print('过')
    else:
        print(i)

打印自幂数

while 循环

i=1
while True:
    sum = 0
    list = str(i)
    long = len(list)
    b= 0
    while b <long:
        sum+=int(list[b])**long
    if sum == i:
        print(i)
    i +=1   

for 循环

for i in range(1,100000000000000000000):
    sum = 0
    list = str(i)
    long = len(list)
    for b in list:
        sum+=int(b)**long
    if sum == i:
        print(i)

打印质数

while 循环

import math
i = 2
while i < 100000000000:
    sqrt = math.sqrt(i)
    count = 0
    for a in range(2, int(sqrt) + 1):
        if (i % a == 0):
            continue
        count += 1
    if count == int(sqrt) - 1:
        print(i)
    i += 1

for 循环

import math
for i in range(2, 1000):
    sqrt = math.sqrt(i)
    count = 0
    for a in range(2, int(sqrt) + 1):
        if (i % a == 0):
            continue
        count += 1
    if count == int(sqrt) - 1:
        print(i)
import math