如何监听浏览器返回按钮，弹框

// 展示离开弹框提示
const showDialog = () => {
  console.log('isStatusChange.value====>', isStatusChange.value)
  dialogVisible.value = isStatusChange.value ? false : true
}
// 监听浏览器返回按钮
const browserGoBack = () => {
  if (window.history && history.pushState) {
    //这里有没有都无所谓，最好是有以防万一
    history.pushState(null, null as unknown as string, document.URL)
    window.addEventListener('popstate', showDialog, false)
  }
}

onUnmounted(() => {
  window.removeEventListener('popstate', showDialog, false)
})