private static void m1() {
String a = "fdfn";
char[] chars = a.toCharArray();
for(char c: chars){
System.out.print(c);//字符
System.out.print(" ");
System.out.println((int)c);//ASCII码十进制数值
}
for(char c: chars){
int c1 = c - 32;
System.out.print((char)c1);//转大写
System.out.print(" ");
System.out.println(c1);//ASCII码十进制数值
}
}
String a = "fdfn";
char c = a.charAt(1);//字符
int c1 = a.charAt(1);//ASCII码十进制数值
实现 strStr() 函数。
给定一个 haystack 字符串和一个 needle 字符串,在 haystack 字符串中找出 needle 字符串出现的第一个位置 (从0开始)。如果不存在,则返回 -1。
示例
输入: haystack = "hello", needle = "ll"
输出: 2
输入: haystack = "aaaaa", needle = "bba"
输出: -1
private static int m1() {
String haystack = "fdfjefhhheelu";
String needle = "helu";
if(needle.length() > haystack.length()){
return -1;
}
if(haystack.length() <=0 || needle.length() <=0){
return -1;
}
char[] chars = haystack.toCharArray();
int start = 0;
int index = 0;
for (int i = 0; i < chars.length; i++) {
if(index >= needle.length()){
return -1;
}
if(chars[i] == needle.toCharArray()[index]){
start = i;
index++;
}else if(index >0 && chars[i] == needle.toCharArray()[0]){
index = 1;
start = i;
}else {
index = 0;
}
if(index == needle.length()){
return start - needle.length() + 1;
}
}
return -1;
}