逻辑题-喝啤酒问题

题目:

现有×瓶啤酒，每3个空瓶子换一瓶啤酒，每7个瓶盖子也可以换一瓶啤酒，问最后可以喝多少瓶啤酒。

这道题, 一开始我完全没思路😭, 听了王争老师讲解, 才有了下面的思路

思路:

java实现

public int drink(int x) {
    int count =x, bottle =x, cap=x;
    while (bottle >=3 || cap >= 7) {
        if(bottle>= 3) {
            bottle = bottle-3;
            count++;
            bottle++;
            cap++;
        }
        if(cap >=7) {
            cap = cap - 7;
            count++;
            bottle++;
            cap++;
        }
    }
    return count;
}

王争老师的解法

public int drink(int x) {
    int count =x, bottle =x, cap=x;
    while (bottle >=3) {
        while (bottle>=3) {
            int change = bottle/3;
            count +=change;
            bottle%=3;
            bottle+=change;
            cap+=change;
        }
        while (cap>=7) {
            int change = cap/7;
            count +=change;
            cap%=7;
            bottle+=change;
            cap+=change;
        }
    }
    return count;
}