$.ajax get传递和接收多个参数

传递参数

let name = "张三"
let age = 18
const data = {
            name:name
            age:age
            }
            
$.ajax({
        type:"get",
        url:url,
        data:data,
        success:function (res) {
            console.log(res)
        })

接收参数

 const name = req.query.name;
 const age = req.query.age;