从左上开始z形打印矩阵中的元素

package class01;

public class Code06_ZigZagPrintMatrix {

	public static void printMatrixZigZag(int[][] matrix) {
		int tR = 0; // 
		int tC = 0;
		int dR = 0;
		int dC = 0;
		int endR = matrix.length - 1;
		int endC = matrix[0].length - 1;
		boolean fromUp = false;
		while (tR != endR + 1) {
			printLevel(matrix, tR, tC, dR, dC, fromUp);
			tR = tC == endC ? tR + 1 : tR;
			tC = tC == endC ? tC : tC + 1;
			dC = dR == endR ? dC + 1 : dC;
			dR = dR == endR ? dR : dR + 1;
			fromUp = !fromUp;
		}
		System.out.println();
	}

	public static void printLevel(int[][] m, int tR, int tC, int dR, int dC,
			boolean f) {
		if (f) {
			while (tR != dR + 1) {
				System.out.print(m[tR++][tC--] + " ");
			}
		} else {
			while (dR != tR - 1) {
				System.out.print(m[dR--][dC++] + " ");
			}
		}
	}

	public static void main(String[] args) {
		int[][] matrix = { { 1, 2, 3, 4 }, { 5, 6, 7, 8 }, { 9, 10, 11, 12 } };
		printMatrixZigZag(matrix);

	}

}

• javascript 版本

let arr = [
  [1,  2,  6,  7,  14],
  [3,  5,  8,  13, 15],
  [4,  9,  12, 16, 19],
  [10, 11, 17, 18, 20]
]
function printMatrixZigZag(matrix) {
  let tR = 0 // 上面A的横坐标
  let tC = 0 // 上面A的纵坐标
  let dR = 0 // 左面B的横坐标
  let dC = 0 // 左面B的纵坐标
  let endR = matrix.length - 1    // 矩阵横坐标终点
  let endC = matrix[0].length - 1 // 矩阵纵坐标终点
  let fromUp = false // 是否是右上往左下的行走方向
  while(tR <= endR + 1) {
    printLevel(matrix, tR,tC,dR,dC,fromUp)
    tR = tC == endC ? tR + 1 : tR;// A点是否下移取决于纵坐标是否到尽头了
    tC = tC == endC ? tC : tC + 1;// 这里条件顺序不能错,严格说是前俩个后两个 两个之间的顺序不能错
    dC = dR == endR ? dC + 1 : dC;// B点是否右移取决于横坐标是否到尽头了
    dR = dR == endR ? dR : dR + 1;// 顺序不能乱
    fromUp = !fromUp
  }
}
function printLevel(matrix,tR,tC,dR,dC,fromUp) {
  if(fromUp) {
    while(tR <= dR) {
      console.log(matrix[tR++][tC--])
    }
  }else {
    while(dR >= tR) {
      console.log(matrix[dR--][dC++])
    }
  }
}
printMatrixZigZag(arr)