js 解析url参数是常见面试题之一,抛出两个拙劣
方法,大家有好的技巧或者有更好的方法,欢迎在评论区讨论!
const url = `https://www.baidu.com/s?tn=15007414_6_dg&ie=utf-8&wd=baidu`
function getParams(url) {
const params = new URLSearchParams(url);
return Object.fromEntries(params.entries())
}
console.log(getParams(url));
function getParams1(url) {
if(url.indexOf(`?`)){
const str = url.split(`?`)[1];
const arr = str.split(`&`);
const res = {}
arr.forEach(item => {
const key = item.split('=')[0]
const value = item.split('=')[1]
res[key] = decodeURIComponent(value)
})
return res
}
}
console.log(getParams1(url));