题目

输入一个二叉树，将它变换为它的镜像。

数据范围

树中节点数量 [0,100][0,100]。

样例

输入树：
      8
     / \
    6  10
   / \ / \
  5  7 9 11

 [8,6,10,5,7,9,11,null,null,null,null,null,null,null,null] 
输出树：
      8
     / \
    10  6
   / \ / \
  11 9 7  5

 [8,10,6,11,9,7,5,null,null,null,null,null,null,null,null]

解析

先交换左右子树，然后如此递归操作左右子树

代码

C++

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    void mirror(TreeNode* root) {
        if (!root) return;
        swap(root->left, root->right);
        mirror(root->left);
        mirror(root->right);
    }
};

Python

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
    def mirror(self, root):
        """
        :type root: TreeNode
        :rtype: void
        """
        if root is None:
            return
        root.left, root.right = root.right, root.left
        self.mirror(root.left)
        self.mirror(root.right)
        

GO

/**
 * Definition for a binary tree node.
 * type TreeNode struct {
 *     Val int
 *     Left *TreeNode
 *     Right *TreeNode
 * }
 */
func mirror(root *TreeNode)  {
    if root == nil {
        return
    }
    root.Left, root.Right = root.Right, root.Left
    mirror(root.Left)
    mirror(root.Right)
}