studs=[{'sid':'103','Chinese':90,'Math':95,'English':92},{'sid':'101','Chinese':80,'Math':85,'English':82},{'sid':'102','Chinese':70,'Math':75,'English':72}]
scores = dict()
for stu in studs:
sv = stu.items() # dict_items([('sid', '103'), ('Chinese', 90), ('Math', 95), ('English', 92)])
L = []
for i in sv:
if i[0] == 'sid':
k = i[1] # 将学号存储下来
else:
L.append(i[1]) # 否则就把成绩加进去
scores[k] = L # 学号对应成绩
# scores -> {'103': [90, 95, 92], '101': [80, 85, 82], '102': [70, 75, 72]}
so = list(scores.items()) # [('103', [90, 95, 92]), ('101', [80, 85, 82]), ('102', [70, 75, 72])]
so.sort(key = lambda x: x[0], reverse = False)
for i in so:
print('{}:{}'.format(i[0], i[1]))
