20221112 - 790. Domino and Tromino Tiling 多米诺和托米诺平铺(动态规划)

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You have two types of tiles: a 2 x 1 domino shape and a tromino shape. You may rotate these shapes.

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Given an integer n, return the number of ways to tile an 2 x n board. Since the answer may be very large, return it modulo 109 + 7.

In a tiling, every square must be covered by a tile. Two tilings are different if and only if there are two 4-directionally adjacent cells on the board such that exactly one of the tilings has both squares occupied by a tile.

Example 1

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Input: n = 3
Output: 5
Explanation: The five different ways are show above.

Example 2

Input: n = 1
Output: 1

Constraints

  • 1 <= n <= 1000

Solution

经典动态规划

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class Solution {
public:
    int numTilings(int n) {
        int mod = 1000000007;
        vector<vector<long long>> dp(n, vector<long long>(4));
        dp[0][0] = 1;
        dp[0][1] = 0;
        dp[0][2] = 0;
        dp[0][3] = 1;
        for (int i = 1; i < n; i++) {
            dp[i][0] = dp[i - 1][3] % mod;
            dp[i][1] = dp[i - 1][0] % mod + dp[i - 1][2] % mod;
            dp[i][2] = dp[i - 1][0] % mod + dp[i - 1][1] % mod;
            dp[i][3] = (dp[i - 1][0] % mod + dp[i - 1][1] % mod + dp[i - 1][2] % mod + dp[i - 1][3] % mod) % mod;
        }
        return dp[n - 1][3];
    }
};

题目链接:790. 多米诺和托米诺平铺 - 力扣(LeetCode)