1.冒泡排序(直接看图)

int[] a = { 1,20,3,0,8,6,7,9,4 }
for (int j = 0
{
Boolean flag = false
for (int i = 0
{
if (a[i] > a[i + 1])
{
int c = a[i]
a[i] = a[i + 1]
a[i + 1] = c
flag = true
}
}
if (!flag)//如果一个数与其他任何一个数都没有交换,说明排序完成,退出
{
break
}
}
Console.Write(string.Join(" ",a))
2.Array.Sort()排序
int[] a = { 1, 20, 3, 0, 8, 6, 7, 9, 4 }
Array.Sort(a)
Console.Write(string.Join(" ", a))
3.有n(n<=100)个整数,已从小到大排序,插入一个数x,使生成的新序列依旧有序
int x = -5
int[] a = { 1,2,3,4,6,7,8,9}
int[] b = new int[a.Length + 1]
int cur = 0
for (int i = 0
{
if (x > a[i])
{
cur = i+1
}
}
for (int i = 0
{
b[i] = a[i]
}
b[cur] = x
for (int i = cur
{
b[i+1] = a[i]
}
Console.Write(string.Join(" ", b))
4.判断一个字符串是否是回文串,eg:elle,abccba
string s = "abccbaa"
bool flag = true
for (int i = 0
{
if (s[i]!=s[s.Length-1-i])
{
Console.Write(false)
flag = false
break
}
}
if (flag)
{
Console.Write(true)
}
5.求气温连续下降天数的最大值,输入36,32,30,33,28,23,22,30,32,输出4
int [] a= { 36,32,30,33,28,23,22,30,32 }
int maxday = 1
int count = 1
for (int i = 0
{
if (a[i] > a[i + 1])
{
count++
maxday = maxday > count ? maxday : count
}
else {
count = 1
}
}
Console.Write(maxday)
6.只包含小写字母的字符串,计算每个字母出现次数,然后输出只出现2次的字母的个数
string a = "aabbccddffhh"
int[] b = new int[a.Length]
int count = 0
for (int i = 0
{
b[a[i] - 'a'] = b[a[i]-'a'] + 1
}
for (int i = 0
{
if (b[i]==2)
{
count++
}
}
Console.WriteLine(string.Join(" ",b))
Console.WriteLine(count)