There is a function signFunc(x) that returns:
1ifxis positive.-1ifxis negative.0ifxis equal to0.
You are given an integer array nums. Let product be the product of all values in the array nums.
Return signFunc(product).
Example 1
Input: nums = [-1,-2,-3,-4,3,2,1]
Output: 1
Explanation: The product of all values in the array is 144, and signFunc(144) = 1
Example 2
Input: nums = [1,5,0,2,-3]
Output: 0
Explanation: The product of all values in the array is 0, and signFunc(0) = 0
Example 3
Input: nums = [-1,1,-1,1,-1]
Output: -1
Explanation: The product of all values in the array is -1, and signFunc(-1) = -1
Constraints
- 1 <= nums.length <= 1000
- -100 <= nums[i] <= 100
Solution
遍历
class Solution {
public:
int arraySign(vector<int>& nums) {
int ret = 1;
for (int i = 0; i < nums.size(); i++) {
if (ret * nums[i] < 0) ret = -1;
else if (ret * nums[i] > 0) ret = 1;
else return 0;
}
return ret;
}
};
优化
只需要更新符号位即可,注意乘法运算的时间比比较运算长
class Solution {
public:
int arraySign(vector<int>& nums) {
int ret = 1;
for (int i = 0; i < nums.size(); i++) {
if (nums[i] == 0) return 0;
else if (nums[i] < 0) ret = -ret;
}
return ret;
}
};