344.反转字符串
题目链接:344. 反转字符串 - 力扣(LeetCode)
调包!疯狂的调包!我是调包侠,调包nb。
总体思路就是 char[]->String->StringBuilder->String->char[]
class Solution {
public void reverseString(char[] s) {
System.arraycopy(new StringBuilder(new String(s)).reverse().toString().toCharArray(), 0, s, 0, s.length);
}
}
双指针法实现:
class Solution {
public void reverseString(char[] s) {
int left = 0, right = s.length - 1;
while(left < right){
s[left] ^= s[right];
s[right] ^= s[left];
s[left] ^= s[right];
left++;
right--;
}
return;
}
}
541. 反转字符串II
题目链接:541. 反转字符串 II - 力扣(LeetCode)
该题目我想到用一个标识符来记录当前区段的字符串是否需要翻转
class Solution {
public String reverseStr(String s, int k) {
StringBuilder stringBuilder = new StringBuilder();
boolean flag = true;
int l = 0;
while(l + k <= s.length()){
if(flag == true){
stringBuilder.append(reverseIt(s.substring(l, l + k)));
flag = false;
}else{
stringBuilder.append(s.substring(l, l + k));
flag = true;
}
l = l + k;
}
if(l < s.length() && flag == true) stringBuilder.append(reverseIt(s.substring(l, s.length())));
else if(l < s.length() && flag == false) stringBuilder.append(s.substring(l, s.length()));
return stringBuilder.toString();
}
public String reverseIt(String s){
return new StringBuilder(s).reverse().toString();
}
}
剑指Offer 05.替换空格
题目链接:剑指 Offer 05. 替换空格 - 力扣(LeetCode)
创建一个StringBuilder用来接受结果字符串。最后将其转换成String
class Solution {
public String replaceSpace(String s) {
StringBuilder stringBuilder = new StringBuilder();
char[] record = s.toCharArray();
for(char c : record){
if(c == ' '){
stringBuilder.append("%20");
}
else{
stringBuilder.append(c);
}
}
return stringBuilder.toString();
}
}
151.翻转字符串里的单词
题目链接:151. 反转字符串中的单词 - 力扣(LeetCode)
这里先给出对应的api解法,其他方法有时间会补充上
// api解法
class Solution {
public String reverseWords(String s) {
// 方法一:利用Java的API
List<String> wordList = Arrays.asList(s.trim().split("\s+"));
Collections.reverse(wordList);
return String.join(" ", wordList);
}
}
剑指Offer58-II.左旋转字符串
题目链接:剑指 Offer 58 - II. 左旋转字符串 - 力扣(LeetCode)
这里给出该题目的api解法。其他解法有空补充
class Solution {
public String reverseLeftWords(String s, int n) {
StringBuilder stringBuilder = new StringBuilder();
stringBuilder.append(s.substring(n,s.length()));
stringBuilder.append(s.substring(0,n));
return stringBuilder.toString();
}
}