解决问题: 在微信app上不能直接点击a标签跳转去苹果商店的地址,有限制
步骤1: 把苹果app下载的地址 apps.apple.com/cn/app/id14… 用草料二维码转化为二维码,地址后面带参数 isShowButton =true (判断)
步骤2: 判断环境如果是在微信app打开,就展示二维码扫码去苹果商店
<div id="appc" v-cloak>
<div class="contentcd">
<img src="./images/文字图片@2x.png?544" class="logo" alt="" srcset="">
<a href="https://a.app.qq.com/o/simple.jsp?pkgname=yiqi.bazi" v-if="isisAndroid">
<img src="./images/down_a@2x.png" @click="" class="buttonleft_c needcenter" alt="" srcset="">
</a>
<!-- 下面是二维码 -->
<block v-if="isInweixin&&!isisAndroid&&!isQQ" class="blockClass">
<img v-if="!isShowButton" src="./images/caoliaoios_code.png" class="caoliaoios_code" alt="" srcset="">
<span v-if="!isShowButton" class="bindtapclass">长按识别</span>
</block>
<!-- 下面是ios 微信显示按钮 -->
<a href="https://apps.apple.com/cn/app/id1462604864">
<div class="buttonleft_weixin" @click="clicktoShop" v-if="isShowButton">
</div>
</a>
<!--下面是 ios 浏览器情况下才显示-->
<a href="https://apps.apple.com/cn/app/id1462604864" v-if="!isisAndroid&&!isInweixin&&!isShowButton">
<img src="./images/down_i@2x.png" class="buttonleft_c needcenter" alt="" srcset="">
</a>
<!--下面是 ios qq浏览器-->
<a href="https://apps.apple.com/cn/app/id1462604864" v-if="!isisAndroid&&isQQ">
<img src="./images/down_i@2x.png" class="buttonleft_c needcenter" alt="" srcset="">
</a>
</div>
</div>
步骤3: 判断扫描二维码重新跳转回本页面是否有参数isShowButton,如果有赋值给变量this.isShowButton
created() {
var u = navigator.userAgent, app = navigator.appVersion;
var isAndroid = u.indexOf('Android') > -1 || u.indexOf('Linux') > -1;
var isiOS = !!u.match(/\(i[^;]+;( U;)? CPU.+Mac OS X/);
if(isAndroid){
this.isisAndroid=true
}else {
this.isisAndroid=false
}
// console.log(this.isisAndroid,'isisAndroid')
var ua = window.navigator.userAgent.toLowerCase();
if(ua.match(/MicroMessenger/i) == 'micromessenger' || ua.match(/_SQ_/i) == '_sq_'){
this.isInweixin=true
} else{
this.isInweixin=false
}
if(ua.match(/QQ/i) == 'qq'){
this.isQQ=true
}
this.isShowButton=this.getQueryVariable('isShowButton')
},
方法获取url里面参数
/**
* 获取url参数
* @param
* @returns void
* @data 2022年6月13日
* @author xiao
*/
getQueryVariable(variable) {
var query = window.location.search.substring(1);
var vars = query.split("&");
for (var i = 0; i < vars.length; i++) {
var pair = vars[i].split("=");
if (pair[0] == variable) {
return pair[1];
}
}
return '';
},