给定一个二叉树的 root ,返回 最长的路径的长度 ,这个路径中的 每个节点具有相同值 。 这条路径可以经过也可以不经过根节点。
两个节点之间的路径长度 由它们之间的边数表示。
示例 1:
输入: root = [5,4,5,1,1,null,5]
输出: 2
示例 2:
输入: root = [1,4,5,4,4,null,5]
输出: 2
提示:
- 树的节点数的范围是
[0, 10^4] -1000 <= Node.val <= 1000- 树的深度将不超过
1000
解题
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number}
*/
var longestUnivaluePath = function (root) {
let longest = 0;
const dfs = (node) => {
let leftCount = 0;
let rightCount = 0;
const { left, right } = node;
if (left) {
let count = dfs(left);
if (left.val === node.val) {
leftCount = count;
}
}
if (right) {
let count = dfs(right);
if (right.val === node.val) {
rightCount = count;
}
}
longest = Math.max(longest, leftCount + rightCount);
return Math.max(leftCount, rightCount) + 1;
};
root && dfs(root);
return longest;
};