反转数组的Java程序

编写一个Java程序，使用for循环来逆转一个数组。在这个例子中，for循环从上到下迭代，并将每个值分配给另一个数组。接下来，我们使用另一个for循环来打印这个反向数组。

packege  RemainingSimplePrograms;

import java.util.Scanner;

public class Example1 { 
private static Scanner sc; 
public static void main(String\[\] args) { 
        int Size, i, j;

	sc = new Scanner(System.in);		
	System.out.print("Enter the size = ");
	Size = sc.nextInt();
	
	double\[\] a = new double\[Size\];
	double\[\] b = new double\[Size\];
	
	System.out.format("Enter %d elements  = ", Size);
	for(i = 0; i < Size; i++) 
	{
		a\[i\] = sc.nextDouble();
	}
	
	for(i = Size - 1, j = 0; i >= 0; i--, j++) 
	{
		b\[j\] = a\[i\];
	}
	
	System.out.println("\\nThe Result");
	for(i = 0; i < Size; i++) 
	{
		System.out.print(b\[i\] + "  ");
	}
}

Enter the size = 4
Enter 4 elements  = 22 67 94 122

The Result
122.0  94.0  67.0  22.0  

使用while循环反转一个数组的Java程序

package RemainingSimplePrograms;

import java.util.Scanner;

public class Example2 { 
private static Scanner sc; 
public static void main(String\[\] args) { 
        int Size, i, j; 
        double temp;

	sc = new Scanner(System.in);		
	System.out.print("Enter the size = ");
	Size = sc.nextInt();
	
	double\[\] a = new double\[Size\];
	
	System.out.format("Enter %d elements  = ", Size);
	for(i = 0; i < Size; i++) 
	{
		a\[i\] = sc.nextDouble();
	}
	
	j = i - 1;
	i = 0;
		
	while(i < j) 
	{
		temp = a\[i\];
		a\[i\] = a\[j\];
		a\[j\] = temp;
		i++;
		j--;
	}
	
	System.out.println("\\nThe Result");
	for(i = 0; i < Size; i++) 
	{
		System.out.print(a\[i\] + "  ");
	}
}

Enter the size = 6
Enter 6 elements  = 11 98.4 29.6 12.9 14.4 12.1

The Result
12.1  14.4  12.9  29.6  98.4  11.0  

在这个例子中，我们没有使用另一个，而是在一个单一的for循环中反转并打印数组。

package RemainingSimplePrograms;

import java.util.Scanner;

public class ReverseAnArray3 {


private static Scanner sc;

public static void main(String\[\] args) {
	
	int Size, i;
	
	sc = new Scanner(System.in);
	
	System.out.print("Enter the Array size = ");
	Size = sc.nextInt();	
	
	double\[\] a = new double\[Size\];
	
	System.out.format("Enter %d Array elements  = ", Size);
	for(i = 0; i < Size; i++) 
	{
		a\[i\] = sc.nextDouble();
	}
	
	System.out.println("\\nThe Result of the Reverse Array");
	for(i = a.length - 1; i >= 0; i--) 
	{
		System.out.print(a\[i\] + "  ");
	}
}

使用递归函数反转一个数组的程序。

package RemainingSimplePrograms;

import java.util.Scanner;

public class Example4 { 
private static Scanner sc; 
public static void main(String\[\] args) { 
        int Size, i;

	sc = new Scanner(System.in);		
	System.out.print("Enter the size = ");
	Size = sc.nextInt();
	
	int\[\] a = new int\[Size\];
	
	System.out.format("Enter %d elements  = ", Size);
	for(i = 0; i < Size; i++) 
	{
		a\[i\] = sc.nextInt();
	}
	
	revArr(a, 0, Size - 1);
	
	System.out.println("\\nThe Result");
	for(i = 0; i < Size; i++) 
	{
		System.out.print(a\[i\] + "  ");
	}
}

public static void revArr(int\[\] a, int start, int end) {
	int temp;
	
	if(start < end)
	{
		temp = a\[start\];
		a\[start\] = a\[end\];
		a\[end\] = temp;
		revArr(a, start + 1, end - 1);
	}
}

Enter the size = 8
Enter 8 elements  = 12 45 32 44 687 17 122 986

The Result
986  122  17  687  44  32  45  12