算法作业0:a+b问题大全(Python实现)

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本文已参与「新人创作礼」活动, 一起开启掘金创作之路。 前言:本科时多数写的a+b problem都是C++实现的。人工智能时代以来(笑死),该全部换成Python实现了。哈哈哈哈哈哈哈。 @TOC

Problem A. A+B I

样例输入

1 2 -1 1

样例输出

3 0

解决:

import sys #引入异常退出
try:
  while(1):
    a,b = input().split() # 获取输入为字符串
    print(int(a)+int(b))# 字符串转为int
catch(EOFError):
  sys.exit()

Problem B. A+B II

样例输入

2 1 2 -1 1

样例输出

3 0

解决:

t = int(input())
for i in range(t):
  a,b = input().split()
  print(int(a)+int(b))
  i = i+1

Problem C. A+B III

样例输入

1 2 -1 1 0 0

样例输出

3 0

解决:

import sys
while(1):
   a,b = input().split()
   a,b = int(a),int(b)
   if a == 0 and b == 0:
      sys.exit()
   else:
      print(a+b)

Problem D. A+B IV

样例输入

5 1 2 3 4 5 2 -1 1 0

样例输出

15 0

实现:

import sys
while(1):
  list1 = input().split()
  list2 = [int(num) for num in list1]
  del list2[0]
  if list2[0] == 0:
     sys.exit()
  print(sum(list2)) #sum函数不能和变量名重复

Problem E. A+B V

样例输入

3 5 1 2 3 4 5 2 -1 1 1 0

样例输出

15 0 0

解决

import sys
try:
    t = int(input())
    while (t):
        list1 = input().split()
        list2 = [int(ele) for ele in list1]
        print(sum(list2[1:]))
        t = t-1
except EOFError:
    sys.exit()   

Problem F. A+B VI

样例输入

4 1 2 3 4 5 1 2 3 4 5

样例输出

10 15

解决

import sys
try:
  while(1):
    list1 = input().split()
    list2 = [int(ele) for ele in list1]
    print(sum(list2[1:]))
except EOFError:
  sys.exit()

Problem G. A+B VII

样例输入

1 5 10 20

样例输出

6 // a blank line 30

解决:

# 必须注意缩进,否则代码会被编译器跳过!
import sys
try:
    flag = 0
    while(1):
        if(flag):
            print("")
        flag = 1
        list1 = input().split()
        list2 = [int(ele) for ele in list1]
        print(sum(list2))
except EOFError:
    sys.exit()

Problem H. A+B VIII

样例输入

3 4 1 2 3 4 5 1 2 3 4 5 3 1 2 3

样例输出 10

15

6 解决:

import sys
try:
    t = int(input())
    flag = 0
    while(t):
        list1 = input().split()
        list2 = [int(ele) for ele in list1]
        if flag:
            print()
        flag = 1
        print(sum(list2[1:]))
        t = t-1
except:
    sys.exit()