模式串匹配

p=abba s=[happy dog dog happy]

var wp=function(p,s){
    const w2c=new Map()
    const c2w=new Map()
    const w=s.split(' ')
    if(p.length!=w.length){
        return false
    }
    for(const [i,v] of w.entries()){
        const ch=p[i]
        if(w2c.has(v)&&w2c.get(w)!=ch||c2w.hash(ch)&&c2w.get(ch)!=v){
            return false
        }
        w2c.set(v,ch)
        c2w.set(ch,v)
    }
    return true
}