344. 反转字符串

85 阅读1分钟

好青年 | leetcode 打卡群 - 打卡记录第 五 天

编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。

不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

示例 1:

输入:s = ["h","e","l","l","o"]
输出:["o","l","l","e","h"]

示例 2:

输入:s = ["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]
/**
 * @param {character[]} s
 * @return {void} Do not return anything, modify s in-place instead.
 */
var reverseString = function (s) {
    // return s.reverse()
    // 左右指针,进行替换
    let left = 0, right = s.length - 1;

    while (left < right) {
        [s[left], s[right]] = [s[right], s[left]];
        left++;
        right--
    }
};