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计算每个雇员每周工作的小时数

假设所有雇员每周工作的小时数存储在一个二维数组中。每行将一个雇 员 7天的工作时间记录在7 列中。例如：右面显示的 数组存储了 8 个雇员的工作时间。编写一个程序，按 照总工时降序的方式显示雇员和他们的总工时。 （用接口及Arrays.sort）

package Homework;
import java.util.Arrays;
interface Comaprable { //用于比较两个员工的接口
    public int comparableTo(Object other);
}
public class Exercise8_4_03 {
    private static int[][] workHours = {         //测试用工时
            {2, 4, 3, 4, 5, 8, 8},
            {7, 3, 4, 3, 3, 4, 4},
            {3, 3, 4, 3, 3, 2, 2},
            {9, 3, 4, 7, 3, 4, 1},
            {3, 5, 4, 3, 6, 3, 8},
            {3, 4, 4, 6, 3, 4, 4},
            {3, 7, 4, 8, 3, 8, 4},
            {6, 3, 5, 9, 2, 7, 9}};

    public static void main(String[] args) {
        int TotalHour[] = new int[8]; //生成一个装员工总工时的数组TotalHour
        int temp;
        for (int a = 0; a < 8; a++) {
            temp = 0;
            for (int b = 0; b < 7; b++) {
                temp += workHours[a][b];
            }
            TotalHour[a] = temp;
        }

        Employee[] staff = new Employee[8];
        for (int i = 0; i < 8; i++) {  //将每个员工的名字与工作时长放进staff数组中
            staff[i] = new Employee("Employee"+i, TotalHour[i]);
        }
        Arrays.sort(staff);

        for (Employee e : staff) {   //打印降序排列的员工及总工时
            System.out.println(e.getName() + " TotalWorkHours=" + e.getTotalHour());
        }
    }
}

class Employee implements Comparable<Employee> {
        private String name;
        private int TotalHour;

        public Employee(String name, int TotalHour) {
            this.name = name;
            this.TotalHour = TotalHour;
        }

        public String getName() {
            return name;
        }

        public int getTotalHour() {
            return TotalHour;
        }

        public  int compareTo(Employee o1) {
            return o1.TotalHour-TotalHour;  //降序排列：o1.TotalHour-TotalHour; 升序排列则为TotalHour-o1.TotalHour;
        }
    }

输出结果如下：