题目: 给定两个整数数组 preorder 和 inorder ,其中 preorder 是二叉树的先序遍历, inorder 是同一棵树的中序遍历,请构造二叉树并返回其根节点。 题目链接
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {number[]} preorder
* @param {number[]} inorder
* @return {TreeNode}
*/
var buildTree = function(preorder, inorder) {
return build(preorder, 0, preorder.length - 1, inorder, 0, inorder.length -1);
};
const build = (preorder, preStart, preEnd, inorder, inStart, inEnd) => {
if (preStart > preEnd) return null;
const rootValue = preorder[preStart];
const rootIndex = inorder.indexOf(rootValue);
const leftTreeSize = rootIndex - inStart;
const root = new TreeNode(rootValue);
root.left = build(preorder, preStart + 1, preStart + leftTreeSize, inorder, inStart, rootIndex - 1);
root.right = build(preorder, preStart + leftTreeSize + 1, preEnd, inorder, rootIndex + 1, inEnd);
return root;
};
解析;
- 时间复杂度: