数组对象去重(待更新)

let costList = [{name: 'a',id: 1}, {name: 'a',id: 2}, {name: 'b',id: 3}, {name: 'c',id: 4},
 {name: 'c',id: 6}, {name: 'b',id: 6}, {name: 'd',id: 7}];

1.reduce方法

根据数组对象的name属性作为条件去重

let Conditions = {};
costList = costList.reduce((preVal, curVal) => {
    // console.log(incomeList,'2')
    Conditions[curVal.name] ? '' : Conditions[curVal.name] = preVal.push(curVal)
    console.log(preVal, '1')
    return preVal
}, []);

2. es6的Map()

根据数组对象的name属性作为条件去重

 let map = new Map();
for (let item of costList) {
    if (!map.has(item.name)) {
        map.set(item.name, item)
    }
    costList = [...map.values()]
};