1. 题目

www.nowcoder.com/practice/03…

2. 考点

1. 列表解包

num, *lis, x, k = s.split(' ')

2. 字符串组成成分一致

# 对字符串排序 就可以查看是否相等
sorted(x) == sorted(i)

核心代码

def test(s: str):
    num, *lis, x, k = s.split(' ')
    k = int(k)
    result = []
    for i in lis:
        x != i and sorted(x) == sorted(i) and result.append(i)
    result = sorted(result)
    print(len(result))
    if len(result) >= k:
        print(result[k - 1])


if __name__ == '__main__':
    try:
        test(input())
    except EOFError:
        pass

4. 精简代码

def test(s: str):
    num, *lis, x, k = s.split(' ')
    k = int(k)
    result = sorted([i for i in lis if x != i and sorted(x) == sorted(i)])
    print(len(result))
    if len(result) >= k:
        print(result[k - 1])


if __name__ == '__main__':
    try:
        test(input())
    except EOFError:
        pass