for (var k = 1; k <= n; k++) { 边界处理
for (var i = 1; i <= m; i++) { 二位数组外层循环
for (var j = 1; j <= n; j++) {二位数组内层循环
if (s1[i - 1] == s2[j - 1] || s2[j - 1] == '?') { 那么 此处的布尔型取决于 上一行 和 上一列的值
else if (s2[j - 1] == '*') {遇到*,则对应的那一列的值都为true
var isMatch = function (s1, s2) {
var m = s1.length, n = s2.length
var dp = new Array(m + 1).fill(false).map(() => new Array(n + 1).fill(false))
dp[0][0] = true
for (var k = 1; k <= n; k++) {
if (dp[0][k - 1] && s2[k - 1] == '*') {
dp[0][k] = true
}
}
for (var i = 1; i <= m; i++) {
for (var j = 1; j <= n; j++) {
if (s1[i - 1] == s2[j - 1] || s2[j - 1] == '?') {
dp[i][j] = dp[i - 1][j - 1]
} else if (s2[j - 1] == '*') {
dp[i][j] = dp[i][j - 1] || dp[i - 1][j]
}
}
}
return dp[m][n]
};