class Solution {
public List<List<Integer>> zigzagLevelOrder(TreeNode root) {
//用一个状态标志来表示吧
boolean leftToRight = true;
List<List<Integer>> res = new ArrayList();
if(root == null) return res;
Queue<TreeNode> queue = new LinkedList();
queue.add(root);
while(!queue.isEmpty()){
int len = queue.size();
List<Integer> list = new ArrayList();
for(int i = 0;i < len;i++){
TreeNode cur = queue.poll();
list.add(cur.val);
if(cur.left != null) queue.add(cur.left);
if(cur.right != null) queue.add(cur.right);
}
if(!leftToRight){
Collections.reverse(list);
}
res.add(list);
leftToRight = !leftToRight;
}
return res;
}
}
标准的BFS + reverse
时间复杂度O(n) 空间复杂度O(n)
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