用两个栈实现队列

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用两个栈实现队列

请用栈实现一个队列,支持如下四种操作:

push(x) – 将元素x插到队尾;
pop() – 将队首的元素弹出,并返回该元素;
peek() – 返回队首元素;
empty() – 返回队列是否为空;

注意:

你只能使用栈的标准操作:push to top,peek/pop from top, size 和 is empty;
如果你选择的编程语言没有栈的标准库,你可以使用list或者deque等模拟栈的操作;
输入数据保证合法,例如,在队列为空时,不会进行pop或者peek等操作;

样例
MyQueue queue = new MyQueue();
queue.push(1);
queue.push(2);
queue.peek();  // returns 1
queue.pop();   // returns 1
queue.empty(); // returns false

时间复杂度O(n)

class MyQueue {

    Stack<Integer> st1 = new Stack();
    Stack<Integer> st2 = new Stack();
    /** Initialize your data structure here. */
    public MyQueue() {

    }
    
    /** Push element x to the back of queue. */
    public void push(int x) {
        st1.push(x);
    }
    
    /** Removes the element from in front of queue and returns that element. */
    public int pop() {
        while(!st1.isEmpty()){
            st2.push(st1.pop());
        }
        int res = st2.pop();
        while(!st2.isEmpty()){
            st1.push(st2.pop());
        }
        return res;
    }
    
    /** Get the front element. */
    public int peek() {
        while(!st1.isEmpty()){
            st2.push(st1.pop());
        }
        int res = st2.peek();
        while(!st2.isEmpty()){
            st1.push(st2.pop());
        }
        return res;
    }
    
    /** Returns whether the queue is empty. */
    public boolean empty() {
        return st1.isEmpty();
    }
}